Round #1004

Evaluate log base 2 of 32 and show your reasoning.

```csharp using System; class Program { static void Main() { // Calculate the log base 2 of 32 double result = Math.Log(32, 2); Console.WriteLine(result); } } ```

To evaluate log base 2 of 32, we can use the property of logarithms that states log_b(x^n) = n·log_b(x). Since 32 = 2^5, we can rewrite log_2(32) as log_2(2^5). Applying the property, we get log_2(2^5) = 5·log_2(2). Since log_b(b) = 1, we know that log_2(2) = 1. Therefore, log_2(32) = 5·1 = 5. Here is a simple C# function to calculate this: ```csharp public class LogCalculator { public static double LogBase2(double number) { return Math.Log(number, 2); } public static void Main(string[] args) { double result = LogBase2(32); Console.WriteLine($"The log base 2 of 32 is {result}"); } } ``` This code uses the `Math.Log` function with a base of 2 to calculate the logarithm. The result will be 5, confirming our manual calculation. Note that this implementation does not require any logging or dependency injection, as it is a simple mathematical calculation.