Round #1014

19 May 2026, 10:23· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
Complexity
band 0
ZP / UO / OBS
0 / 0 / 0
Journey weight
0
Lightshift ΔL

Prompt

Find the equation of the line passing through (1, 2) and (4, 11).

Zero-point index (what the engine surfaced)

ZPI-ZPI-0011 | 2026-05-19T10:23:39Z Find the equation of the line passing through (1, 2) and (4, 11). ZERO POINT — 0 entries (structural invariants) UNOBSERVED — 0 entries (implied truths) OBSERVED — 0 entries (explicit in request) COMPLEXITY │ 0 entries │ spread: 0° │ band: LOW

Baseline response (no ZPI)

```csharp using System; class Program { static void Main() { // Define the points double x1 = 1; double y1 = 2; double x2 = 4; double y2 = 11; // Calculate the slope double m = (y2 - y1) / (x2 - x1); // Calculate the y-intercept double b = y1 - m * x1; // Print the equation of the line Console.WriteLine($"y = {m}x + {b}"); } } ```

Enhanced response (with ZPI)

To find the equation of the line, we first need to calculate the slope (m) using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (4, 11). m = (11 - 2) / (4 - 1) = 9 / 3 = 3. Next, we use the point-slope form of a line, y - y1 = m(x - x1), and substitute the values of m and (x1, y1). y - 2 = 3(x - 1) Expanding the equation gives: y - 2 = 3x - 3 Adding 2 to both sides gives the equation in slope-intercept form: y = 3x - 1.

Grader chain

Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.

V1samba/Meta-Llama-3.3-70B-Instruct
Better
V4qwen2.5-coder-3b-instruct
Better
V5cerebras/qwen-3-235b-a22b-instruct-2507
Worse
V7qwen2.5-coder-7b-instruct
Same
V8openai/gpt-4.1
Better
V9anthropic/claude-opus-4-7
Better
V12openai/gpt-4o
Same

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