Round #1014
19 May 2026, 10:23· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 0 / 0 / 0
- Journey weight
- 0
- Lightshift ΔL
- —
Prompt
Find the equation of the line passing through (1, 2) and (4, 11).
Zero-point index (what the engine surfaced)
ZPI-ZPI-0011 | 2026-05-19T10:23:39Z
Find the equation of the line passing through (1, 2) and (4, 11).
ZERO POINT — 0 entries (structural invariants)
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 0 entries (explicit in request)
COMPLEXITY │ 0 entries │ spread: 0° │ band: LOW
Baseline response (no ZPI)
```csharp
using System;
class Program
{
static void Main()
{
// Define the points
double x1 = 1;
double y1 = 2;
double x2 = 4;
double y2 = 11;
// Calculate the slope
double m = (y2 - y1) / (x2 - x1);
// Calculate the y-intercept
double b = y1 - m * x1;
// Print the equation of the line
Console.WriteLine($"y = {m}x + {b}");
}
}
```
Enhanced response (with ZPI)
To find the equation of the line, we first need to calculate the slope (m) using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) = (1, 2) and (x2, y2) = (4, 11).
m = (11 - 2) / (4 - 1) = 9 / 3 = 3.
Next, we use the point-slope form of a line, y - y1 = m(x - x1), and substitute the values of m and (x1, y1).
y - 2 = 3(x - 1)
Expanding the equation gives:
y - 2 = 3x - 3
Adding 2 to both sides gives the equation in slope-intercept form:
y = 3x - 1.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
WorseV7qwen2.5-coder-7b-instruct
SameV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
BetterV12openai/gpt-4o
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