Round #1051

19 May 2026, 18:16· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
Complexity
band 0
ZP / UO / OBS
3 / 0 / 2
Journey weight
417
Lightshift ΔL

Prompt

Compute the limit of (x^2 - 4) / (x - 2) as x approaches 2. Give the exact value.

Zero-point index (what the engine surfaced)

ZPI-ZPI-0010 | 2026-05-19T18:16:14Z Compute the limit of (x^2 - 4) / (x - 2) as x approaches 2. Give the exact value. ZERO POINT — 3 entries (structural invariants) ● hsl(29.04, 100%, 15%) ε-δ definition of limit [contract] ● hsl(186.89, 100%, 15%) L'Hôpital's rule for 0/0 and ∞/∞ forms [contract] ● hsl(75.09, 100%, 15%) continuity at a point [contract] UNOBSERVED — 0 entries (implied truths) OBSERVED — 2 entries (explicit in request) ◉ hsl(92.31, 100%, 22%) value [feature] ◉ hsl(151.79, 100%, 15%) / [feature] COMPLEXITY │ 5 entries │ spread: 59° │ band: LOW

Baseline response (no ZPI)

## Step 1: Factor the numerator The numerator, \(x^2 - 4\), can be factored into \((x + 2)(x - 2)\) because it is a difference of squares. ## Step 2: Rewrite the expression with the factored numerator The expression becomes \(\frac{(x + 2)(x - 2)}{x - 2}\). ## Step 3: Cancel out the common factor We can cancel out the \((x - 2)\) from both the numerator and the denominator, as long as \(x \neq 2\), to get \(x + 2\). ## Step 4: Evaluate the limit as x approaches 2 Now that the expression simplifies to \(x + 2\), we can evaluate the limit as \(x\) approaches 2 by substituting \(x = 2\) into the simplified expression: \(2 + 2 = 4\). The final answer is: $\boxed{4}$

Enhanced response (with ZPI)

```csharp using System; public class LimitCalculator { public static double ComputeLimit() { // Factor the numerator // (x^2 - 4) = (x + 2)(x - 2) // Cancel out the common factor (x - 2) // ((x + 2)(x - 2)) / (x - 2) = x + 2 // Evaluate the limit as x approaches 2 double limit = 2 + 2; return limit; } public static void Main(string[] args) { double limit = ComputeLimit(); Console.WriteLine(limit); } } ``` This C# code calculates the limit of (x^2 - 4) / (x - 2) as x approaches 2 by factoring the numerator and canceling out the common factor, resulting in a limit of 4.

Grader chain

Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.

V1samba/Meta-Llama-3.3-70B-Instruct
Better
V4qwen2.5-coder-3b-instruct
Better
V5openrouter/qwen/qwen3-235b-a22b-2507
Worse
V7qwen2.5-coder-7b-instruct
Better
V8openai/gpt-4.1
Better
V9anthropic/claude-opus-4-7
Better
V12openai/gpt-4o
Better

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