Round #1063
19 May 2026, 18:19· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 3 / 0 / 0
- Journey weight
- 255
- Lightshift ΔL
- —
Prompt
Compute the number of permutations of 7 distinct objects taken 3 at a time, P(7, 3). Give the exact integer.
Zero-point index (what the engine surfaced)
ZPI-ZPI-0022 | 2026-05-19T18:19:00Z
Compute the number of permutations of 7 distinct objects taken 3 at a time, P(7, 3). Give the exact integer.
ZERO POINT — 3 entries (structural invariants)
● hsl(123.87, 100%, 15%) P(n,k) = n!/(n-k)! permutations [contract]
● hsl(115.54, 100%, 15%) C(n,k) = n!/(k!(n-k)!) combinations [contract]
● hsl(45.86, 100%, 15%) multiplication principle for independent choices [contract]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 0 entries (explicit in request)
COMPLEXITY │ 3 entries │ spread: 0° │ band: LOW
Baseline response (no ZPI)
## Step 1: Understand the concept of permutations
To solve this problem, we first need to understand what permutations are. Permutations refer to the arrangement of objects in a specific order. When we are asked to find the number of permutations of 7 distinct objects taken 3 at a time, we are essentially looking for the number of ways to arrange 3 objects out of 7 in a specific order.
## Step 2: Apply the formula for permutations
The formula for permutations of n objects taken r at a time is given by P(n, r) = n! / (n-r)!, where "!" denotes factorial, which is the product of all positive integers up to that number. For our problem, n = 7 (total distinct objects) and r = 3 (objects taken at a time).
## Step 3: Calculate the factorial of n (7!)
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040.
## Step 4: Calculate the factorial of (n-r) ((7-3)!)
(7-3)! = 4! = 4 * 3 * 2 * 1 = 24.
## Step 5: Apply the values to the permutations formula
P(7, 3) = 7! / (7-3)! = 5040 / 24.
## Step 6: Perform the division
5040 / 24 = 210.
The final answer is: $\boxed{210}$
Enhanced response (with ZPI)
```csharp
using System;
public class Program
{
public static void Main()
{
Console.WriteLine(Permutation(7, 3));
}
public static long Permutation(int n, int k)
{
if (k > n)
{
throw new ArgumentException("k cannot be greater than n");
}
long result = 1;
for (int i = n; i > n - k; i--)
{
result *= i;
}
return result;
}
}
```
The number of permutations of 7 distinct objects taken 3 at a time is 210.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
BetterV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
WorseV12openai/gpt-4o
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