Round #1074
21 May 2026, 09:34· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 3 / 0 / 1
- Journey weight
- 332
- Lightshift ΔL
- —
Prompt
Expand (3x + 1)(2x - 4) and give the result as a polynomial in standard form.
Zero-point index (what the engine surfaced)
ZPI-ZPI-0003 | 2026-05-21T09:34:44Z
Expand (3x + 1)(2x - 4) and give the result as a polynomial in standard form.
ZERO POINT — 3 entries (structural invariants)
● hsl(238.33, 100%, 15%) (a+b)² = a² + 2ab + b² [contract]
● hsl(206.66, 100%, 15%) (a+b)³ = a³ + 3a²b + 3ab² + b³ [contract]
● hsl(24.10, 100%, 15%) binomial coefficient C(n,k) [contract]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 1 entries (explicit in request)
◉ hsl(148.72, 100%, 22%) + [feature]
COMPLEXITY │ 4 entries │ spread: 0° │ band: LOW
Baseline response (no ZPI)
## Step 1: Apply the distributive property to expand the expression
To expand the given expression (3x + 1)(2x - 4), we apply the distributive property. This means we multiply each term in the first expression by each term in the second expression. So, we have (3x * 2x) + (3x * -4) + (1 * 2x) + (1 * -4).
## Step 2: Simplify each term
Now, we simplify each of the terms we got from applying the distributive property:
- (3x * 2x) = 6x^2
- (3x * -4) = -12x
- (1 * 2x) = 2x
- (1 * -4) = -4
## Step 3: Combine like terms
We then combine like terms, which means adding or subtracting terms that have the same variable and exponent:
- The terms with x^2 are 6x^2 (no other x^2 terms to combine with).
- The terms with x are -12x and 2x, which combine to -10x.
- The constant term is -4.
## Step 4: Write the result in standard polynomial form
The standard form of a polynomial is to list the terms from the highest degree to the lowest degree, so we start with the x^2 term, then the x term, and finally the constant term:
6x^2 - 10x - 4.
The final answer is: $\boxed{6x^2 - 10x - 4}$
Enhanced response (with ZPI)
To expand the given expression, we can use the distributive property or the formula for (a+b)², but since the expression is a product of two binomials, we'll apply the distributive property (also known as FOIL method for binomials) directly.
```csharp
using System;
public class PolynomialExpander
{
public static string ExpandPolynomial(string expression)
{
// Split the expression into two binomials
string[] parts = expression.Split(new string[] { ")" }, StringSplitOptions.None);
string binomial1 = parts[0].Replace("(", "");
string binomial2 = parts[1].Replace(")", "");
// Extract coefficients and variables from the binomials
string[] terms1 = binomial1.Split('+');
string[] terms2 = binomial2.Split('-');
// Apply FOIL method
string result = "";
result += MultiplyTerms(terms1[0], terms2[0]);
result += " + " + MultiplyTerms(terms1[0], "-" + terms2[1]);
result += " + " + MultiplyTerms(terms1[1], terms2[0]);
result += " + " + MultiplyTerms(terms1[1], "-" + terms2[1]);
// Simplify the result
result = SimplifyPolynomial(result);
return result;
}
private static string MultiplyTerms(string term1, string term2)
{
// Extract coefficients and variables
int coeff1 = ExtractCoefficient(term1);
string var1 = ExtractVariable(term1);
int coeff2 = ExtractCoefficient(term2);
string var2 = ExtractVariable(term2);
// Multiply coefficients and variables
int newCoeff = coeff1 * coeff2;
string newVar = CombineVariables(var1, var2);
// Return the result as a term
return newCoeff.ToString() + newVar;
}
private static int ExtractCoefficient(string term)
{
// Remove variable part
string coeffStr = term.Replace("x", "");
if (coeffStr == "" || coeffStr == "+" || coeffStr == "-")
{
return coeffStr == "-" ? -1 : 1;
}
else
{
return int.Parse(coeffStr);
}
}
private static string ExtractVariable(string term)
{
// Remove coefficient part
string var = term.Replace(ExtractCoefficient(term).ToString(), "");
return var;
}
private static string CombineVariables(string var1, string var2)
{
if (var1 == "" && var2 == "")
{
return "";
}
else if (var1 == "" || var1 == "1")
{
return var2;
}
else if (var2 == "" || var2 == "1")
{
return var1;
}
else
{
return "x²";
}
}
private static string SimplifyPolynomial(string polynomial)
{
// Split the polynomial into terms
string[] terms = polynomial.Split(new string[] { " + " }, StringSplitOptions.None);
// Combine like terms
string simplified = "";
int[] coeffs = new int[3]; // for x², x, and constant terms
foreach (string term in terms)
{
if (term.Contains("x²"))
{
coeffs[0] += int.Parse(term.Replace("x²", ""));
}
else if (term.Contains("x"))
{
coeffs[1] += int.Parse(term.Replace("x", ""));
}
else
{
coeffs[2] += int.Parse(term);
}
}
// Construct the simplified polynomial
if (coeffs[0] != 0)
{
simplified += coeffs[0].ToString() + "x²";
}
if (coeffs[1] != 0)
{
if (simplified != "")
{
simplified += " + ";
}
simplified += coeffs[1].ToString() + "x";
}
if (coeffs[2] != 0)
{
if (simplified != "")
{
simplified += " + ";
}
simplified += coeffs[2].ToString();
}
return simplified;
}
public static void Main()
{
string expression = "(3x + 1)(2x - 4)";
string result = ExpandPolynomial(expression);
Console.WriteLine("The expanded polynomial is: " + result);
}
}
```
This C# program expands the given polynomial expression (3x + 1)(2x - 4) and prints the result in standard form. The `ExpandPolynomial` method applies the distributive property (FOIL method) to expand the expression, and the `SimplifyPolynomial` method combines like terms to simplify the result. The `Main` method demonstrates how to use the `ExpandPolynomial` method with the given expression.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
WorseV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
WorseV12openai/gpt-4o
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