Round #1078

21 May 2026, 09:35· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
Complexity
band 1
ZP / UO / OBS
9 / 0 / 2
Journey weight
802
Lightshift ΔL

Prompt

Evaluate the indefinite integral of 5x^4 + 2e^x with respect to x. Give the antiderivative and include the constant of integration.

Zero-point index (what the engine surfaced)

ZPI-ZPI-0007 | 2026-05-21T09:35:42Z Evaluate the indefinite integral of 5x^4 + 2e^x with respect to x. Give the antiderivative and include the constant of integration. ZERO POINT — 9 entries (structural invariants) ● hsl(135.43, 100%, 25%) f'(x) = lim_{h→0} (f(x+h) - f(x))/h [contract] ● hsl(134.71, 100%, 25%) power rule d/dx(x^n) = n·x^(n-1) [contract] ● hsl(172.48, 100%, 25%) linearity of differentiation [contract] ● hsl(248.11, 100%, 25%) ∫x^n dx = x^(n+1)/(n+1) + C (n ≠ -1) [contract] ● hsl(103.19, 100%, 25%) linearity of integration [contract] ● hsl(160.65, 100%, 25%) constant of integration C [contract] ● hsl(347.63, 100%, 25%) ∫_a^b f(x) dx = F(b) - F(a) where F'=f [contract] ● hsl(287.61, 100%, 25%) FTC Part 1 d/dx ∫_a^x f(t) dt = f(x) [contract] ● hsl(190.47, 100%, 25%) differentiation and integration as inverse operations [contract] UNOBSERVED — 0 entries (implied truths) OBSERVED — 2 entries (explicit in request) ◉ hsl(98.46, 100%, 50%) with [feature] ◉ hsl(148.72, 100%, 22%) + [feature] COMPLEXITY │ 11 entries │ spread: 50° │ band: MEDIUM

Baseline response (no ZPI)

To evaluate the indefinite integral of 5x^4 + 2e^x with respect to x, we'll integrate each term separately. The integral of x^n with respect to x is (x^(n+1))/(n+1), so the integral of 5x^4 is: ∫5x^4 dx = 5∫x^4 dx = 5(x^5)/5 = x^5 The integral of e^x with respect to x is e^x, so the integral of 2e^x is: ∫2e^x dx = 2∫e^x dx = 2e^x Now, we combine the results: ∫(5x^4 + 2e^x) dx = x^5 + 2e^x + C where C is the constant of integration. So, the antiderivative of 5x^4 + 2e^x is x^5 + 2e^x + C.

Enhanced response (with ZPI)

To evaluate the indefinite integral of 5x^4 + 2e^x, we can apply the linearity of integration and the power rule of integration. The integral of 5x^4 is 5 * (x^(4+1))/(4+1) = x^5. The integral of 2e^x is 2 * e^x, since the integral of e^x is e^x. So, the antiderivative of 5x^4 + 2e^x is x^5 + 2e^x + C, where C is the constant of integration. Here is the C# code to calculate and print the antiderivative: ```csharp using System; public class Program { public static void Main() { string antiderivative = CalculateAntiderivative(); Console.WriteLine("The antiderivative is: " + antiderivative); } public static string CalculateAntiderivative() { // Define the function string function = "5x^4 + 2e^x"; // Calculate the antiderivative string antiderivative = "x^5 + 2e^x + C"; return antiderivative; } } ``` This code defines a function `CalculateAntiderivative` that returns the antiderivative of the given function, and then prints it to the console. Note that this code does not actually perform the integration, but rather returns a pre-calculated result. In a real-world application, you would likely use a library or framework that can perform symbolic integration, such as Math.NET Symbolics. Here is an example using Math.NET Symbolics: ```csharp using MathNet.Symbolics; public class Program { public static void Main() { string antiderivative = CalculateAntiderivative(); Console.WriteLine("The antiderivative is: " + antiderivative); } public static string CalculateAntiderivative() { // Define the variable var x = Symbol.Variable("x"); // Define the function var function = 5 * x**4 + 2 * Exp(x); // Calculate the antiderivative var antiderivative = Integrate(function, x); return antiderivative.ToString(); } } ``` This code uses the Math.NET Symbolics library to define the function and calculate its antiderivative. The result is then printed to the console.

Grader chain

Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.

V1samba/Meta-Llama-3.3-70B-Instruct
Better
V4qwen2.5-coder-3b-instruct
Better
V5cerebras/qwen-3-235b-a22b-instruct-2507
Worse
V7qwen2.5-coder-7b-instruct
Better
V8openai/gpt-4.1
Better
V9anthropic/claude-opus-4-7
Better
V12openai/gpt-4o
Better

Comments

Our grader said what it said. What do you say? Comment as a guest below.

No comments yet. Be the first to say what you make of this round.

← back to all rounds