Round #1078
21 May 2026, 09:35· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 1
- ZP / UO / OBS
- 9 / 0 / 2
- Journey weight
- 802
- Lightshift ΔL
- —
Prompt
Evaluate the indefinite integral of 5x^4 + 2e^x with respect to x. Give the antiderivative and include the constant of integration.
Zero-point index (what the engine surfaced)
ZPI-ZPI-0007 | 2026-05-21T09:35:42Z
Evaluate the indefinite integral of 5x^4 + 2e^x with respect to x. Give the antiderivative and include the constant of integration.
ZERO POINT — 9 entries (structural invariants)
● hsl(135.43, 100%, 25%) f'(x) = lim_{h→0} (f(x+h) - f(x))/h [contract]
● hsl(134.71, 100%, 25%) power rule d/dx(x^n) = n·x^(n-1) [contract]
● hsl(172.48, 100%, 25%) linearity of differentiation [contract]
● hsl(248.11, 100%, 25%) ∫x^n dx = x^(n+1)/(n+1) + C (n ≠ -1) [contract]
● hsl(103.19, 100%, 25%) linearity of integration [contract]
● hsl(160.65, 100%, 25%) constant of integration C [contract]
● hsl(347.63, 100%, 25%) ∫_a^b f(x) dx = F(b) - F(a) where F'=f [contract]
● hsl(287.61, 100%, 25%) FTC Part 1 d/dx ∫_a^x f(t) dt = f(x) [contract]
● hsl(190.47, 100%, 25%) differentiation and integration as inverse operations [contract]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 2 entries (explicit in request)
◉ hsl(98.46, 100%, 50%) with [feature]
◉ hsl(148.72, 100%, 22%) + [feature]
COMPLEXITY │ 11 entries │ spread: 50° │ band: MEDIUM
Baseline response (no ZPI)
To evaluate the indefinite integral of 5x^4 + 2e^x with respect to x, we'll integrate each term separately.
The integral of x^n with respect to x is (x^(n+1))/(n+1), so the integral of 5x^4 is:
∫5x^4 dx = 5∫x^4 dx = 5(x^5)/5 = x^5
The integral of e^x with respect to x is e^x, so the integral of 2e^x is:
∫2e^x dx = 2∫e^x dx = 2e^x
Now, we combine the results:
∫(5x^4 + 2e^x) dx = x^5 + 2e^x + C
where C is the constant of integration.
So, the antiderivative of 5x^4 + 2e^x is x^5 + 2e^x + C.
Enhanced response (with ZPI)
To evaluate the indefinite integral of 5x^4 + 2e^x, we can apply the linearity of integration and the power rule of integration.
The integral of 5x^4 is 5 * (x^(4+1))/(4+1) = x^5.
The integral of 2e^x is 2 * e^x, since the integral of e^x is e^x.
So, the antiderivative of 5x^4 + 2e^x is x^5 + 2e^x + C, where C is the constant of integration.
Here is the C# code to calculate and print the antiderivative:
```csharp
using System;
public class Program
{
public static void Main()
{
string antiderivative = CalculateAntiderivative();
Console.WriteLine("The antiderivative is: " + antiderivative);
}
public static string CalculateAntiderivative()
{
// Define the function
string function = "5x^4 + 2e^x";
// Calculate the antiderivative
string antiderivative = "x^5 + 2e^x + C";
return antiderivative;
}
}
```
This code defines a function `CalculateAntiderivative` that returns the antiderivative of the given function, and then prints it to the console.
Note that this code does not actually perform the integration, but rather returns a pre-calculated result. In a real-world application, you would likely use a library or framework that can perform symbolic integration, such as Math.NET Symbolics.
Here is an example using Math.NET Symbolics:
```csharp
using MathNet.Symbolics;
public class Program
{
public static void Main()
{
string antiderivative = CalculateAntiderivative();
Console.WriteLine("The antiderivative is: " + antiderivative);
}
public static string CalculateAntiderivative()
{
// Define the variable
var x = Symbol.Variable("x");
// Define the function
var function = 5 * x**4 + 2 * Exp(x);
// Calculate the antiderivative
var antiderivative = Integrate(function, x);
return antiderivative.ToString();
}
}
```
This code uses the Math.NET Symbolics library to define the function and calculate its antiderivative. The result is then printed to the console.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
WorseV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
BetterV12openai/gpt-4o
BetterComments
Our grader said what it said. What do you say? Comment as a guest below.
No comments yet. Be the first to say what you make of this round.