Round #1093
21 May 2026, 09:39· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 3 / 0 / 0
- Journey weight
- 225
- Lightshift ΔL
- —
Prompt
How many distinct arrangements are there of the letters in the word "STATISTICS"? Give the exact integer.
Zero-point index (what the engine surfaced)
ZPI-ZPI-0022 | 2026-05-21T09:39:06Z
How many distinct arrangements are there of the letters in the word "STATISTICS"? Give the exact integer.
ZERO POINT — 3 entries (structural invariants)
● hsl(123.87, 100%, 25%) P(n,k) = n!/(n-k)! permutations [contract]
● hsl(115.54, 100%, 25%) C(n,k) = n!/(k!(n-k)!) combinations [contract]
● hsl(45.86, 100%, 25%) multiplication principle for independent choices [contract]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 0 entries (explicit in request)
COMPLEXITY │ 3 entries │ spread: 0° │ band: LOW
Baseline response (no ZPI)
## Step 1: Count the total number of letters in the word "STATISTICS"
The word "STATISTICS" has 10 letters.
## Step 2: Identify and count the repeating letters in the word "STATISTICS"
Upon inspection, we find that the letter "S" repeats 3 times, the letter "T" repeats 3 times, the letter "A" repeats 1 time, the letter "I" repeats 2 times, and the letter "C" repeats 1 time.
## Step 3: Apply the formula for permutations of a set with repeating elements to calculate the number of distinct arrangements
The formula for permutations of a set of n objects where there are n1, n2, etc. identical objects is n! / (n1! * n2! * ...).
For "STATISTICS", n = 10 (total letters), n1 = 3 (for S), n2 = 3 (for T), n3 = 1 (for A), n4 = 2 (for I), and n5 = 1 (for C).
So, the formula becomes 10! / (3! * 3! * 1! * 2! * 1!).
## Step 4: Calculate the factorial of each number needed for the formula
10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800,
3! = 3 * 2 * 1 = 6,
3! = 6,
1! = 1,
2! = 2 * 1 = 2,
1! = 1.
## Step 5: Plug the factorial values into the formula and calculate the result
Result = 3628800 / (6 * 6 * 1 * 2 * 1) = 3628800 / 72 = 50400.
The final answer is: $\boxed{50400}$
Enhanced response (with ZPI)
To calculate the number of distinct arrangements of the letters in the word "STATISTICS", we can use the formula for permutations of a multiset, which is given by n! / (k1! * k2! * ... * km!), where n is the total number of items and k1, k2, ..., km are the multiplicities of each item.
In this case, we have 10 letters: S, T, A, T, I, S, T, I, C, S. The multiplicities are:
- S: 3
- T: 3
- A: 1
- I: 2
- C: 1
So, the number of distinct arrangements is 10! / (3! * 3! * 1! * 2! * 1!).
Here is the C# code to calculate this:
```csharp
using System;
class Program
{
static void Main()
{
Console.WriteLine(CalculateArrangements());
}
static long CalculateArrangements()
{
// Define the factorial function
long Factorial(int n)
{
long result = 1;
for (int i = 2; i <= n; i++)
{
result *= i;
}
return result;
}
// Define the multiplicities of each letter
int s = 3;
int t = 3;
int a = 1;
int i = 2;
int c = 1;
int n = 10;
// Calculate the number of distinct arrangements
long arrangements = Factorial(n) / (Factorial(s) * Factorial(t) * Factorial(a) * Factorial(i) * Factorial(c));
return arrangements;
}
}
```
When you run this code, it will output the exact integer number of distinct arrangements of the letters in the word "STATISTICS".
The result is: 2520 * 10 * 9 * 8 * 7 * 6 * 5 * 4 / (6 * 2 * 1 * 2 * 1) = 2520 * 30240 / 24 = 30240 * 210 = 6350400 / 24 = 264600.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
WorseV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
WorseV12openai/gpt-4o
WorseComments
Our grader said what it said. What do you say? Comment as a guest below.
No comments yet. Be the first to say what you make of this round.