Round #1097
21 May 2026, 09:40· math· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 3 / 0 / 4
- Journey weight
- 568
- Lightshift ΔL
- —
Prompt
Compute the limit of the sequence a_n = (5n^2 + 2) / (2n^2 - n + 4) as n approaches infinity. Give the exact value.
Zero-point index (what the engine surfaced)
ZPI-ZPI-0026 | 2026-05-21T09:40:03Z
Compute the limit of the sequence a_n = (5n^2 + 2) / (2n^2 - n + 4) as n approaches infinity. Give the exact value.
ZERO POINT — 3 entries (structural invariants)
● hsl(29.04, 100%, 15%) ε-δ definition of limit [contract]
● hsl(186.89, 100%, 15%) L'Hôpital's rule for 0/0 and ∞/∞ forms [contract]
● hsl(75.09, 100%, 15%) continuity at a point [contract]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 4 entries (explicit in request)
◉ hsl(92.31, 100%, 22%) value [feature]
◉ hsl(148.72, 100%, 22%) + [feature]
◉ hsl(151.79, 100%, 15%) / [feature]
◉ hsl(175.38, 100%, 27%) = [feature]
COMPLEXITY │ 7 entries │ spread: 83° │ band: LOW
Baseline response (no ZPI)
## Step 1: Identify the sequence and the limit in question
The sequence given is \(a_n = \frac{5n^2 + 2}{2n^2 - n + 4}\), and we need to find the limit as \(n\) approaches infinity.
## Step 2: Determine the method to evaluate the limit
To evaluate the limit of a sequence as \(n\) approaches infinity, especially for rational functions like this one, we can compare the degrees of the polynomials in the numerator and denominator. If they are the same, the limit will be the ratio of the leading coefficients.
## Step 3: Compare the degrees of the numerator and denominator
The degree of the numerator \(5n^2 + 2\) is 2, and the degree of the denominator \(2n^2 - n + 4\) is also 2. Since they have the same degree, the limit as \(n\) approaches infinity will be the ratio of the leading coefficients.
## Step 4: Calculate the limit
The leading coefficient of the numerator is 5, and the leading coefficient of the denominator is 2. Therefore, the limit as \(n\) approaches infinity is \(\frac{5}{2}\).
The final answer is: $\boxed{\frac{5}{2}}$
Enhanced response (with ZPI)
To compute the limit of the sequence `a_n = (5n^2 + 2) / (2n^2 - n + 4)` as `n` approaches infinity, we can use the following C# code:
```csharp
using System;
public class LimitCalculator
{
public static double CalculateLimit()
{
// Define the function for the sequence
Func<double, double> sequence = n => (5 * Math.Pow(n, 2) + 2) / (2 * Math.Pow(n, 2) - n + 4);
// Calculate the limit as n approaches infinity
double limit = 5.0 / 2.0; // Since the highest order terms dominate as n approaches infinity
return limit;
}
public static void Main(string[] args)
{
double limit = CalculateLimit();
Console.WriteLine("The limit of the sequence as n approaches infinity is: " + limit);
}
}
```
This code calculates the limit by dividing the highest order terms in the numerator and denominator, which dominate as `n` approaches infinity. The result is `5/2` or `2.5`.
Alternatively, we can apply L'Hôpital's rule, but in this case, it's not necessary since the limit can be evaluated directly by considering the dominant terms.
The limit of the sequence `a_n` as `n` approaches infinity is `2.5`.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5cerebras/qwen-3-235b-a22b-instruct-2507
WorseV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
WorseV12openai/gpt-4o
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