Round #549

09 May 2026, 23:11· csharp· Meta-Llama-3.3-70B-Instruct· r13-clean-hints
Complexity
band 0
ZP / UO / OBS
0 / 0 / 0
Journey weight
0
Lightshift ΔL

Prompt

Convert 0.625 to a fraction in lowest terms.

Zero-point index (what the engine surfaced)

ZPI-ZPI-0008 | 2026-05-09T23:11:28Z Convert 0.625 to a fraction in lowest terms. ZERO POINT — 0 entries (structural invariants) UNOBSERVED — 0 entries (implied truths) OBSERVED — 0 entries (explicit in request) COMPLEXITY │ 0 entries │ spread: 0° │ band: LOW

Baseline response (no ZPI)

## Step 1: We need to convert the decimal 0.625 to a fraction. To start, we'll express 0.625 as 625/1000, since there are three decimal places. ## Step 2: Simplify the fraction by finding the greatest common divisor (GCD) of the numerator and denominator. The GCD of 625 and 1000 is 125, because 125 is the largest number that divides both 625 and 1000 without leaving a remainder. ## Step 3: Divide both the numerator and denominator by the GCD to simplify the fraction. Dividing 625 by 125 gives 5, and dividing 1000 by 125 gives 8. So, the simplified fraction is 5/8. The final answer is: $\boxed{\frac{5}{8}}$

Enhanced response (with ZPI)

```csharp using System; public class Program { public static void Main() { double decimalNumber = 0.625; var fraction = DecimalToFraction(decimalNumber); Console.WriteLine($"{decimalNumber} as a fraction is {fraction.Numerator}/{fraction.Denominator}"); } public static (int Numerator, int Denominator) DecimalToFraction(double decimalNumber) { int sign = Math.Sign(decimalNumber); decimalNumber = Math.Abs(decimalNumber); int integerPart = (int)decimalNumber; double fractionalPart = decimalNumber - integerPart; int precision = 1000000; // arbitrary high precision int denominator = precision; int numerator = (int)(fractionalPart * precision); int gcd = GCD(numerator, denominator); numerator /= gcd; denominator /= gcd; numerator += integerPart * (denominator / precision); gcd = GCD(numerator, denominator); numerator /= gcd; denominator /= gcd; if (sign == -1) { numerator = -numerator; } return (numerator, denominator); } public static int GCD(int a, int b) { while (b != 0) { int temp = b; b = a % b; a = temp; } return a; } } ```

Grader chain

Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.

V1samba/Meta-Llama-3.3-70B-Instruct
Better
V4qwen2.5-coder-3b-instruct
Better
V5openrouter/qwen/qwen3-235b-a22b-2507
Worse
V7qwen2.5-coder-7b-instruct
Better
V8openai/gpt-4.1
Better
V9anthropic/claude-opus-4-7
Worse
V12openai/gpt-4o
Better

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