Round #553

What is the perimeter of a triangle with sides 5, 7, and 10?

**Calculating the Perimeter of a Triangle** To calculate the perimeter of a triangle, you need to add up the lengths of all three sides. ### Formula Perimeter = side1 + side2 + side3 ### Code ```csharp using System; public class TrianglePerimeter { public static int CalculatePerimeter(int side1, int side2, int side3) { return side1 + side2 + side3; } public static void Main(string[] args) { int side1 = 5; int side2 = 7; int side3 = 10; int perimeter = CalculatePerimeter(side1, side2, side3); Console.WriteLine("The perimeter of the triangle is: " + perimeter); } } ``` ### Explanation 1. Define a method `CalculatePerimeter` that takes three integers as parameters (side1, side2, side3). 2. Inside the method, add up the three sides and return the result. 3. In the `Main` method, define the lengths of the three sides. 4. Call the `CalculatePerimeter` method with the side lengths and store the result in the `perimeter` variable. 5. Print the perimeter to the console. ### Result When you run this code, it will output: ``` The perimeter of the triangle is: 22 ``` Therefore, the perimeter of the triangle with sides 5, 7, and 10 is **22**.

```csharp using System; public class Program { public static void Main() { Console.WriteLine(CalculatePerimeter(5, 7, 10)); } public static double CalculatePerimeter(double a, double b, double c) { // Check if the sides can form a triangle if (a + b <= c || a + c <= b || b + c <= a) { throw new ArgumentException("The sides cannot form a triangle"); } // Calculate the perimeter double perimeter = a + b + c; return perimeter; } } ```