Round #628

Solve for x: 3x + 7 = 22

To solve the equation \(3x + 7 = 22\) for \(x\), follow these steps: 1. Subtract 7 from both sides of the equation to isolate the term with \(x\): \[ 3x + 7 - 7 = 22 - 7 \] Simplifying this, we get: \[ 3x = 15 \] 2. Divide both sides by 3 to solve for \(x\): \[ \frac{3x}{3} = \frac{15}{3} \] Simplifying this, we get: \[ x = 5 \] So, the solution is \(x = 5\).

To solve the equation \(3x + 7 = 22\) for \(x\), we need to isolate \(x\) on one side of the equation. Here's how you can do it step-by-step: 1. Subtract 7 from both sides of the equation: \[ 3x + 7 - 7 = 22 - 7 \] Simplifying this, we get: \[ 3x = 15 \] 2. Divide both sides by 3 to solve for \(x\): \[ \frac{3x}{3} = \frac{15}{3} \] Simplifying this, we get: \[ x = 5 \] So, the solution to the equation \(3x + 7 = 22\) is \(x = 5\). Here's a simple C# program that demonstrates how to solve this equation using basic arithmetic operations: ```csharp using System; class Program { static void Main() { // Coefficients and constant from the equation 3x + 7 = 22 double coefficient = 3; double constant = 7; double result = 22; // Solve for x double x = (result - constant) / coefficient; // Output the solution Console.WriteLine($"The solution to the equation is: x = {x}"); } } ``` ### Explanation: 1. **Coefficients and Constant**: We define the coefficients and constants from the equation \(3x + 7 = 22\). 2. **Solving for \(x\)**: Using basic arithmetic operations, we isolate \(x\) by subtracting the constant from the result and then dividing by the coefficient. 3. **Output**: The solution is printed to the console. This program is straightforward and demonstrates how to solve a linear equation using C#.