Round #646
10 May 2026, 08:29· csharp· qwen2.5-coder-7b-instruct· r13-clean-hints
- Complexity
- band 0
- ZP / UO / OBS
- 3 / 0 / 1
- Journey weight
- 235
- Lightshift ΔL
- —
Prompt
If x plus y equals 10 and x minus y equals 4, what are x and y?
Zero-point index (what the engine surfaced)
ZPI-ZPI-0020 | 2026-05-10T08:29:07Z
If x plus y equals 10 and x minus y equals 4, what are x and y?
ZERO POINT — 3 entries (structural invariants)
● hsl(7.18, 100%, 50%) class [feature]
● hsl(0.00, 100%, 50%) public [feature]
● hsl(84.10, 100%, 50%) namespace [feature]
UNOBSERVED — 0 entries (implied truths)
OBSERVED — 1 entries (explicit in request)
◉ hsl(74.87, 100%, 15%) equals [feature]
COMPLEXITY │ 4 entries │ spread: 0° │ band: LOW
Baseline response (no ZPI)
To solve the system of equations:
\[ x + y = 10 \]
\[ x - y = 4 \]
We can add these two equations together to eliminate \( y \):
\[ (x + y) + (x - y) = 10 + 4 \]
\[ 2x = 14 \]
\[ x = 7 \]
Now that we have \( x = 7 \), we can substitute this value back into the first equation to solve for \( y \):
\[ 7 + y = 10 \]
\[ y = 3 \]
So, the solution is \( x = 7 \) and \( y = 3 \).
Enhanced response (with ZPI)
To solve the system of equations \(x + y = 10\) and \(x - y = 4\), we can use basic algebraic manipulation. Adding these two equations together will eliminate \(y\) and allow us to solve for \(x\):
\[ (x + y) + (x - y) = 10 + 4 \]
\[ 2x = 14 \]
\[ x = 7 \]
Substituting \(x = 7\) back into the first equation:
\[ 7 + y = 10 \]
\[ y = 3 \]
So, \(x = 7\) and \(y = 3\).
Here is a simple C# program to demonstrate this solution:
```csharp
using System;
class Program
{
static void Main()
{
// Coefficients from the equations
double a1 = 1.0; // coefficient of x in first equation
double b1 = 1.0; // coefficient of y in first equation
double c1 = 10.0; // constant term in first equation
double a2 = 1.0; // coefficient of x in second equation
double b2 = -1.0; // coefficient of y in second equation
double c2 = 4.0; // constant term in second equation
// Solving the system of equations
double determinant = a1 * b2 - a2 * b1;
if (determinant == 0)
{
Console.WriteLine("The system of equations has no unique solution.");
}
else
{
double x = (c1 * b2 - c2 * b1) / determinant;
double y = (a1 * c2 - a2 * c1) / determinant;
Console.WriteLine($"x = {x}");
Console.WriteLine($"y = {y}");
}
}
}
```
### Explanation:
1. **Coefficients Extraction**: The coefficients from the equations are extracted and stored in variables.
2. **Determinant Calculation**: The determinant of the coefficient matrix is calculated to check if the system has a unique solution.
3. **Solution Calculation**: If the determinant is non-zero, the values of \(x\) and \(y\) are calculated using Cramer's rule.
4. **Output**: The results are printed to the console.
This program demonstrates how to solve a system of linear equations using basic algebraic methods in C#.
Grader chain
Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.
V1samba/Meta-Llama-3.3-70B-Instruct
BetterV4qwen2.5-coder-3b-instruct
BetterV5openrouter/qwen/qwen3-235b-a22b-2507
BetterV7qwen2.5-coder-7b-instruct
BetterV8openai/gpt-4.1
BetterV9anthropic/claude-opus-4-7
BetterV12openai/gpt-4o
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