Round #769

10 May 2026, 17:34· csharp· Meta-Llama-3.3-70B-Instruct· r14-length-bound
Complexity
band 0
ZP / UO / OBS
3 / 0 / 1
Journey weight
235
Lightshift ΔL
—

Prompt

Find x: 5 times the quantity x minus 3 equals 20

Zero-point index (what the engine surfaced)

ZPI-ZPI-0015 | 2026-05-10T17:34:12Z Find x: 5 times the quantity x minus 3 equals 20 ZERO POINT — 3 entries (structural invariants) ● hsl(7.18, 100%, 50%) class [feature] ● hsl(0.00, 100%, 50%) public [feature] ● hsl(84.10, 100%, 50%) namespace [feature] UNOBSERVED — 0 entries (implied truths) OBSERVED — 1 entries (explicit in request) ◉ hsl(74.87, 100%, 15%) equals [feature] COMPLEXITY │ 4 entries │ spread: 0° │ band: LOW

Baseline response (no ZPI)

To solve for x, we need to translate the given equation into a mathematical expression and then solve for x. The equation is: 5 times the quantity x minus 3 equals 20 This can be written as: 5(x - 3) = 20 To solve for x, we need to follow the order of operations (PEMDAS): 1. Distribute the 5 to the terms inside the parentheses: 5x - 15 = 20 2. Add 15 to both sides of the equation to isolate the term with x: 5x - 15 + 15 = 20 + 15 5x = 35 3. Divide both sides of the equation by 5 to solve for x: 5x / 5 = 35 / 5 x = 7 Therefore, the value of x is 7.

Enhanced response (with ZPI)

To find x, we can set up the equation as 5(x - 3) = 20. Expanding the equation gives 5x - 15 = 20. Adding 15 to both sides gives 5x = 35. Dividing both sides by 5 gives x = 7. The value of x is 7.

Grader chain

Each grader reads the same baseline + enhanced pair and casts an independent verdict. Disagreement is the framework's own signal — not noise to be averaged away.

V1samba/Meta-Llama-3.3-70B-Instruct
Same
V4qwen2.5-coder-3b-instruct
Better
V5openrouter/qwen/qwen3-235b-a22b-2507
Same
V7qwen2.5-coder-7b-instruct
Same
V8openai/gpt-4.1
Same
V9anthropic/claude-opus-4-7
Same
V12openai/gpt-4o
Same

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